How to use two-variable equations to model real-life situations
Two-variable equations can be used to model real-life situations involving two unknown quantities related to each other. For example, suppose you want to buy some apples and bananas from a store. The apples cost 1each,andthebananascost0.50 each. You have $10 to spend, and you want to buy 15 fruits. How many apples and bananas can you buy?
To answer this question, we can write two equations representing the situation. One equation relates the number of apples (x) and bananas (y) to the total number of fruits (15).
x + y = 15
The other equation relates the number of apples (x) and bananas (y) to the total cost ($10).
1x + 0.5y = 10
These two equations form a system of equations we can solve by any method we learned: substitution, elimination, or graphing. For example, using elimination, we can multiply the first equation by -0.5 and add it to the second equation to eliminate y.
-0.5(x + y = 15)
+ (1x + 0.5y = 10)
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-0.5x - 0.5y = -7.5
+ x + 0.5y = 10
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0.5x = 2.5
Then, we can solve for x and plug it into either equation to find y.
0.5x = 2.5
x = 2.5/0.5
x = 5
1x + 0.5y = 10
1(5) + 0.5y = 10
5 + 0.5y = 10
0.5y = 10 - 5
0.5y = 5
y = 5/0.5
y = 10
The solution is (x, y) = (5, 10). This means you can buy 5 apples and 10 bananas with $10.
However, this answer does not make sense in the context of the problem because you cannot buy fractions of fruits. So, we must look for another solution with whole numbers for x and y.
One way is to graph the two equations and see where they intersect on the coordinate plane.
[Graph of x+y=15 and x+0.5y=10]
The graph shows that the two lines intersect at the point (5, 10). This means another solution is (x, y) = (5, 10). This means you can buy 5 apples and 10 bananas with $10. This answer makes sense in the context of the problem because it has whole numbers for x and y, and it satisfies both equations.
One possible way to buy 15 fruits with $10 is to buy 5 apples and 10 bananas.